Optimal. Leaf size=27 \[ \frac {\text {Li}_2\left (\frac {c (a-b x)}{a+b x}\right )}{2 a b} \]
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Rubi [A] time = 0.13, antiderivative size = 27, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.086, Rules used = {2517, 2502, 2315} \[ \frac {\text {PolyLog}\left (2,\frac {c (a-b x)}{a+b x}\right )}{2 a b} \]
Antiderivative was successfully verified.
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Rule 2315
Rule 2502
Rule 2517
Rubi steps
\begin {align*} \int \frac {\log \left (1-\frac {c (a-b x)}{a+b x}\right )}{(a-b x) (a+b x)} \, dx &=\int \frac {\log \left (\frac {a (1-c)+b (1+c) x}{a+b x}\right )}{(a-b x) (a+b x)} \, dx\\ &=\frac {\operatorname {Subst}\left (\int \frac {\log (x)}{1-x} \, dx,x,\frac {a (1-c)+b (1+c) x}{a+b x}\right )}{2 a b}\\ &=\frac {\text {Li}_2\left (\frac {c (a-b x)}{a+b x}\right )}{2 a b}\\ \end {align*}
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Mathematica [B] time = 0.16, size = 252, normalized size = 9.33 \[ \frac {2 \text {Li}_2\left (\frac {(c+1) (a-b x)}{2 a}\right )-2 \text {Li}_2\left (\frac {(c+1) (a+b x)}{2 a c}\right )+\log ^2\left (\frac {2 a c}{(c+1) (a+b x)}\right )+2 \log \left (-\frac {a (-c)+a+b (c+1) x}{2 a c}\right ) \log \left (\frac {2 a c}{(c+1) (a+b x)}\right )-2 \log \left (\frac {a (-c)+a+b (c+1) x}{a+b x}\right ) \log \left (\frac {2 a c}{(c+1) (a+b x)}\right )+2 \log (a-b x) \log \left (\frac {a (-c)+a+b (c+1) x}{2 a}\right )-2 \log (a-b x) \log \left (\frac {a (-c)+a+b (c+1) x}{a+b x}\right )-2 \text {Li}_2\left (\frac {a-b x}{2 a}\right )-2 \log (a-b x) \log \left (\frac {a+b x}{2 a}\right )}{4 a b} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.42, size = 34, normalized size = 1.26 \[ \frac {{\rm Li}_2\left (\frac {a c - {\left (b c + b\right )} x - a}{b x + a} + 1\right )}{2 \, a b} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 24, normalized size = 0.89 \[ \frac {\dilog \left (-\frac {2 a c}{b x +a}+c +1\right )}{2 a b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.52, size = 243, normalized size = 9.00 \[ \frac {1}{2} \, {\left (\frac {\log \left (b x + a\right )}{a b} - \frac {\log \left (b x - a\right )}{a b}\right )} \log \left (\frac {{\left (b x - a\right )} c}{b x + a} + 1\right ) + \frac {\log \left (b x + a\right )^{2} - 2 \, \log \left (b x + a\right ) \log \left (b x - a\right )}{4 \, a b} + \frac {\log \left (b x - a\right ) \log \left (\frac {b {\left (c + 1\right )} x - a {\left (c + 1\right )}}{2 \, a} + 1\right ) + {\rm Li}_2\left (-\frac {b {\left (c + 1\right )} x - a {\left (c + 1\right )}}{2 \, a}\right )}{2 \, a b} + \frac {\log \left (b x + a\right ) \log \left (-\frac {b x + a}{2 \, a} + 1\right ) + {\rm Li}_2\left (\frac {b x + a}{2 \, a}\right )}{2 \, a b} - \frac {\log \left (b x + a\right ) \log \left (-\frac {b {\left (c + 1\right )} x + a {\left (c + 1\right )}}{2 \, a c} + 1\right ) + {\rm Li}_2\left (\frac {b {\left (c + 1\right )} x + a {\left (c + 1\right )}}{2 \, a c}\right )}{2 \, a b} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.04 \[ \int \frac {\ln \left (1-\frac {c\,\left (a-b\,x\right )}{a+b\,x}\right )}{\left (a+b\,x\right )\,\left (a-b\,x\right )} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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